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yKpoI14uk [10]
4 years ago
12

Divide the following polynomials: (12x3 + 9x)/3x (8x4y3 – 4x7y5)/(2xy2) (4x3 +5x2 +3x)/x

Mathematics
1 answer:
zheka24 [161]4 years ago
5 0
Before starting, there's a formula that will be crucial to solving all this.

The formula states the following:
\dfrac{a+b}{c}= \dfrac{a}{c }+ \dfrac{b}{c}

Polynomial 1:

\dfrac{12x^3+9x}{3x}

Use the formula shown in the beginning of this answer.

\dfrac{12x^3}{3x}+ \dfrac{9x}{3x}

Now, we only have to simplify each term.
Since you're tackling problems such as these, you should be familiar on exponential rules, so I hope you can follow along.

\dfrac{(4x^2)(3x)}{3x}+ \dfrac{3(3x)}{3x}

=4x^2+3

Polynomial 2:

\dfrac{8x^4 y^3 - 4x^7 y^5}{2xy^2}

Use the formula shown in the beginning of the answer

\dfrac{8x^4 y^3}{2xy^2} - \dfrac{4x^7 y^5}{2xy^2}

= \dfrac{(4x^3 y)(2xy^2)}{2xy^2} - \dfrac{(2x^6 y^3)(2xy^2)}{2xy^2}

=4x^3y-2x^6y^3

Polynomial 3:

\dfrac{4x^3+5x^2+3x}{x}

Use the formula shown in the beginning of the problem (pretty much the same for 3 terms as well).

\dfrac{4x^3}{x}+\dfrac{5x^2}{x}+\dfrac{3x}{x}

=4x^2+5x+3

If you have any comments/questions, feel free to comment and I'll be happy to clarify.
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The temperature falls from 0 degrees to Negative 12 and one-fourth degrees in 3 and one-half hours. Which expression finds the c
ANEK [815]

Answer:

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Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

Step-by-step explanation:

A temperature falls from 0 to  - 12\dfrac{1}{4}     in     3\dfrac{1}{2} \ hours

Which expression finds the change in temperature per hour.

From the above given information;

The initial temperature is 0

The final temperature is  - 12\dfrac{1}{4}  

The change in temperature is \Delta T = T_2  -  T_1

\Delta  T = -12\dfrac{1}{4} -0

\Delta T = -12.25

Thus;

-12.25 ° = 3.5 hours

To find the change in x°   per hour; we have;

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The expression used to find the change in temperature per hour is Algebraic expression

From above if we cross multiply ; we have;

(- 12.25° × 1 hour) = (x° × 3.5 hour)

Divide both sides by 3.5 hours; we have:

\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}

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x° = - 3\dfrac{1}{2}

Thus per hour; the temperature falls at the rate of - 3\dfrac{1}{2}^0

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