Can someone pls help me with some Unit Circle problems?
1 answer:
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VERTEX
To determine the vertex (coordinate x) of parabola y = ax² + bx + c, use this following formula
x vertex =
y = x² - 2x - 48
a = 1, b = -2, c = -48
plug in the numbers
x vertex =
x vertex =
x vertex =
x vertex = 1
To find y vertex, substitute the value of x vertex to the parabola equation
y = x² - 2x - 48
y = 1² - 2(1) - 48
y = 1 - 2 - 48
y = -49
The vertex is (1, -49)
X-INTERCEPT
x-intercept located in x axis, that means y = 0. Substitute y = 0 to the parabola equation
x² - 2x - 48 = y
x² - 2x - 48 = 0
(x - 8)(x + 6) = 0
x = 8 or x = -6
The x-intercepts are (8,0) and (-6,0)
The answer is first option
To determine the vertex (coordinate x) of parabola y = ax² + bx + c, use this following formula
x vertex =
y = x² - 2x - 48
a = 1, b = -2, c = -48
plug in the numbers
x vertex =
x vertex =
x vertex =
x vertex = 1
To find y vertex, substitute the value of x vertex to the parabola equation
y = x² - 2x - 48
y = 1² - 2(1) - 48
y = 1 - 2 - 48
y = -49
The vertex is (1, -49)
X-INTERCEPT
x-intercept located in x axis, that means y = 0. Substitute y = 0 to the parabola equation
x² - 2x - 48 = y
x² - 2x - 48 = 0
(x - 8)(x + 6) = 0
x = 8 or x = -6
The x-intercepts are (8,0) and (-6,0)
The answer is first option