Answer:
Step-by-step explanation:
We can solve this in either of two approaches: Mathematically or Graphically.
<u>Mathematically</u>
y=-(3/4)(x-4)^2+12 where y is the height of the ball, and x is the time, in seconds.
We want to know how many seconds for the height to be 0, so y=0.
0 = -(3/4)(x-4)^2+12
-12 = -(3/4)(x-4)^2
12*(4/3) = (x-4)^2
16 = (x-4)^2
x = 8 and 0 (the initial point).]
It will reach the ground in 8 seconds
<u>Graphically</u>
Plot the function and find the time, x, when the graph passes through the x axis (after t = 0). Attached.
The answer is -x^2 -4 because f(x) is x^2 so -x^2 would be the opposite going downwards. And the graph is on the -4 spot so it’s -4
If 93% of the bar is silver, then the bar is 0.93*8.15 ounces of silver. Solving that makes there 7.58ish ounces of silver in the bar
Answer:
a = - 2
Step-by-step explanation:
calculate the slope of the 2 given points and equate to 0.75
m = 
with (x₁, y₁ ) = (4, a ) and (x₂, y₂ ) = (8, 1 )
m = 
= 
then equating
= 0.75 ( multiply both sides by 4 to clear the fraction )
1 - a = 3 ( subtract 1 from both sides )
- a = 2 ( multiply both sides by - 1 )
a = - 2
The correct answer is 58/7 (decimal: 8,28....)
