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navik [9.2K]
2 years ago
11

A player kicks a soccer ball off of the ground. The height of the ball is modeled by the equation h(t)=-\frac34\left(t-4\right)^

2+12h(t)=− 3/4 (t−4)^2 +12.
After how many seconds does the ball hit the ground?
Mathematics
1 answer:
Aneli [31]2 years ago
6 0

Answer:

Step-by-step explanation:

We can solve this in either of two approaches:  Mathematically or Graphically.

<u>Mathematically</u>

y=-(3/4)(x-4)^2+12  where y is the height of the ball, and x is the time, in seconds.

We want to know how many seconds for the height to be 0, so y=0.

0 = -(3/4)(x-4)^2+12

-12 = -(3/4)(x-4)^2

12*(4/3) = (x-4)^2

16 = (x-4)^2

x = 8 and 0 (the initial point).]

It will reach the ground in 8 seconds

<u>Graphically</u>

Plot the function and find the time, x, when the graph passes through the x axis (after t = 0).  Attached.

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Answer:

Area of the given fan is 763.4 cm²

Step-by-step explanation:

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Here, angle θ = Central angle subtended by the arc

r = Radius of the circle

Since, fan is in the form of a sector of a circle with radius = 27 cm

Measure of the central angle subtended by the arc FN = ∠FAN = 120°

Area of the fan = \frac{120}{360}(\pi )(27)^2

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                         = 243π

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3 years ago
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Answer:

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Step-by-step explanation:

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kirill115 [55]

Answer:

The required expression is y=250,000-24,000 t

Step-by-step explanation:

Consider the provided information.

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This can be written as: (0, 250,000)

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That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m=\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}

Rate of change=m=\frac{Rise}{Run}=\frac{-240,000}{10}

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Answer:

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Step-by-step explanation:

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