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2 years ago

THIS IS WORTH 40 POINTS HELP

Mathematics

2 answers:

nataly862011 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

Meeting ID: 621 872 6773

Passcode: UL4qmA

joja [24]2 years ago

4 0

Answer:

Step-by-step explanation:

I sure of it learned it in 3rd

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Calculate the length of AC to one decimal place in the trapezium below.

a_sh-v [17]

Answer:

First we will split trapezium on two geometric figure.

One is rectangle and the second is right triangle.

When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Good luck!!

7 0

2 years ago

5.4+ 3(52-15 +2) What is it

iragen [17]

Answer:

122.4

Step-by-step explanation:

Remember PEMDAS

Parentheses

Exponents

Multiply

Divide

Add

Subtract

(52-15+2)=39

39x3=117

117+5.4=122.4

3 0

2 years ago

Read 2 more answers

Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.

wolverine [178]

Answer:

$t_7 =\frac{5}{729}$

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) = $\frac{1}{3}$

The nth term of a geometric sequence is given as:

$t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}$