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3 years ago

The larger cube’s volume is about blank cm

Mathematics

1 answer:

padilas [110]3 years ago

3 0

Volume = mass divided by density.

You are given the mass and density for the smaller cube so you can calculate it's volume:

Volume = 20 / 7.87 = 2.541 cubic cm's.

Now you are told the larger cube has 2 times the volume:

Volume of larger cube = 2.541 x 2 = 5.08 cubic cm's.

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The volume of a right circular cone is found using the equation V = 1 3 π r 2 h . Which equation represents the volume solved fo

alex41 [277]

Solving for a variable in an equation means, we are changing the subject of formula of the equation.

The equation of r is: $\mathbf{r = \sqrt{\frac{3V}{\pi h}}}$

The equation is given as:

$\mathbf{V = \frac 13 \pi r^2h}$

We start by multiplying both sides by 3

$\mathbf{V \times 3= \frac 13 \pi r^2h \times 3}$

Rewrite as:

$\mathbf{3V= \pi r^2h}$

Divide both sides by $\mathbf{\pi h}$

$\mathbf{\frac{3V}{\pi h}= \frac{\pi r^2h}{\pi h}}$

Cancel out common factors

$\mathbf{\frac{3V}{\pi h}= r^2}$

Take square roots of both sides

$\mathbf{\sqrt{\frac{3V}{\pi h}}= \sqrt{r^2}}$

Evaluate the right-hand sides

$\mathbf{\sqrt{\frac{3V}{\pi h}}= r}$

Make r the subject

$\mathbf{r = \sqrt{\frac{3V}{\pi h}}}$

Hence, the resulting equating for r is:

$\mathbf{r = \sqrt{\frac{3V}{\pi h}}}$

Read more about the subject of formulas at:

brainly.com/question/21866313

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3 years ago

Identify if the question is

Hatshy [7]

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Potatoes sell for $.25 per pound at the produce market.Write an equation for the cost c of p pounds of potatoes

morpeh [17]

I hope this helps you

if per pound is $25

how much cost ?

C=25/pounds

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the net of the rectangular prism is shown below. use a ruler to measure the dimensions of the net to the nearest half centimeter

Arte-miy333 [17]

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A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

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