Analyze the graph Which inequality represents the

A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med

Troyanec [42]

The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test - No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is $\frac{0.0396}{0.0396+0.0096}= \frac{33}{41}$

The probability of someone picked at random has cancer given that test result indicates no cancer is $\frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}$

7 0

3 years ago

For the function g(x)=3-8(1/4)^2-x

Reika [66]

Using function concepts, it is found that:

a) The y-intercept is y = 2.5.

b) The horizontal asymptote is x = 3.

c) The function is decreasing.

d) The domain is $(-\infty,\infty)$ and the range is $(-\infty,3)$ .
e) The graph is given at the end of the answer.

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The given function is:

$g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}$

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Question a:

The y-intercept is g(0), thus:

$g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5$

The y-intercept is y = 2.5.

------------------------------------

Question b:

The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.

$\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3$

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$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty$

Thus, the horizontal asymptote is x = 3.

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Question c:

The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.

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Question d:

Exponential function has no restrictions in the domain, so it is all real values, that is $(-\infty,\infty)$ .
From the limits in item c, the range is: $(-\infty,3)$

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The sketching of the graph is given appended at the end of this answer.

A similar problem is given at brainly.com/question/16533631

8 0

3 years ago

Help me please! I would appreciate it! :)

GenaCL600 [577]

Answer:

y = 11 1/2

Step-by-step explanation:

7y - 63 = y + 3

-y. -7

6y - 63 = 3

+ 63. + 63

6y = 69

/6. /6

y = 11 1/2

3 0

3 years ago

Read 2 more answers

A jar contains five purple six yellow eight green and 5 orange jelly beans what is the probability of selecting a yellow jelly B

Stella [2.4K]

Answer:

Step-by-step explanation:

First you have to add up everything and get the answer which is 24. Then you have to consider that there are 6 yellow jelly beans. So you would have to put it as a fraction. Which would be... 6/24 hope I helped

5 0

4 years ago

Number 4 i don’t know how to do this one

Kruka [31]

Answer:

r= 3 h = 6 then use 3^2 + 6^2 = l^2

Step-by-step explanation:

3 0

3 years ago