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pav-90 [236]
3 years ago
8

Evaluate each expression for x = 6 and for x = 3. Based on your results, do you know whether the two expressions are equivalent?

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0
Idk idk idk i reall dont know that is hard but good luck
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Brainliest,plz help
labwork [276]

4 sqrt (32) + 6 sqrt (50)

4 sqrt (16*2) + 6 sqrt (2*25)

4 sqrt (16)*sqrt(2) + 6 sqrt (2)*sqrt(25)

4 *4*sqrt(2)+6sqrt(2)*5

16sqrt(2)+30sqrt(2)

46sqrt(2)


4 0
3 years ago
I’m confused please help
mart [117]

Answer:

im guessing the answer is 43.7

Step-by-step explanation:

7 0
2 years ago
Where is 2/4 on the number line with a number line of on 3 ticks?
KIM [24]
2 to the left is 3 your very welcome hope this helps
4 0
3 years ago
To solve a system of inequalities so you can graph it how do you change these two equations into something like the two that are
Zigmanuir [339]
Explanation

Problem #2

We must find the solution to the following system of inequalities:

\begin{gathered} 3x-2y\leq4, \\ x+3y\leq6. \end{gathered}

(1) We solve for y the first inequality:

-2y\leq4-3x.

Now, we multiply both sides of the inequality by (-1), this changes the signs on both sides and inverts the inequality symbol:

\begin{gathered} 2y\ge-4+3x, \\ y\ge\frac{3}{2}x-2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) over the line:

y=\frac{3}{2}x-2.

This line has:

• slope m = 3/2,

,

• y-intercept b = -2.

(2) We solve for y the second inequality:

\begin{gathered} x+3y\leq6, \\ 3y\leq6-x, \\ y\leq-\frac{1}{3}x+2. \end{gathered}

The solution to this inequality is the set of all the points (x, y) below the line:

y=-\frac{1}{3}x+2.

This line has:

• slope m = -1/3,

,

• y-intercept b = 2.

(3) Plotting the lines of points (1) and (2), and painting the region:

• over the line from point (1),

,

• and below the line from point (2),

we get the following graph:

Answer

The points that satisfy both inequalities are given by the intersection of the blue and red regions:

8 0
1 year ago
Pls help me with this multiple choice !
lana66690 [7]

Answer:

D

Step-by-step explanation:

\sin(60)  =  \frac{6 \sqrt{3} }{x}  \\ x =  \frac{6 \sqrt{3} }{ \sin(60) }  = 12 \\  \tan(60)  =  \frac{6 \sqrt{3} }{y}   \\ y =  \frac{6 \sqrt{3} }{ \tan(60) }  =   6

8 0
3 years ago
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