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3 years ago

PLEASE HELP IDHD >~<

Mathematics

1 answer:

kupik [55]3 years ago

8 0

Answer:

multiply the height and width of each side to get the area

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3. The following data was collected from a simple random sample from a process (an infinite population). 13 15 14 16 12 a. The p

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Given the data:

13 15 14 16 12

The point estimate of the population mean will be :

ΣX/ n

X = Given data points

N = sample size

ΣX = (13 + 15 + 14 + 16 + 12) = 70

N = 5

Hence,

ΣX/ N = 70 / 5

Point estimate of population mean = 14

3 0

3 years ago

Please answer the question

shusha [124]

The answer should be C. 3

6 0

3 years ago

During a month, the average temperature in day time of a placewas 430C. The average temperature during night was recorded to be

klasskru [66]

Answer:

Difference between average day temperature and average night temperature = 70°

Step-by-step explanation:

Given;

Average day temperature = 43° C

Average night temperature = -30° C

Find:

Difference between average day temperature and average night temperature

Computation:

Difference between average day temperature and average night temperature = Average day temperature - Average night temperature

Difference between average day temperature and average night temperature = 43 - (-30)

Difference between average day temperature and average night temperature = 70°

7 0

2 years ago

He completed 2 and 4/5 rows of grapes each hour he worked after completing 140 rows of grapes how many hours had he worked?

algol [13]

Step-by-step explanation:

Divide 140 by $2\frac{4}{5}$ to represent the amount of hours he worked.

To make dividing easier, $2\frac{4}{5}$ can also represent 2.8 as a decimal.

$\frac{140}{2.8} =50$

He has worked 50 hours after completing 140 rows of grapes.

4 0

2 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$

therefore

the answer is

$581.25$

6 0

3 years ago

Read 2 more answers