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Step2247 [10]
3 years ago
7

What is the midpoint of the line segment with endpoints at (4, 12) and (-10, 32)?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

The midpoint is (-3,22)

Step-by-step explanation:

Use the midpoint formula (x1+x2 /2, y1+y2 /2)

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Each row in the table shows how a picture was enlarged or reduced
Fed [463]

Answer:

1. Tall Dog

2. Small Dog

3. Regular Dog

4. Fat Dog

Step-by-step explanation:

It's simple. Look at the problem ;)

8 0
3 years ago
3x+2y=6 and y=1/3x-11 perpendicular or parallel
IgorLugansk [536]

Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.

For two lines  y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate  k1 and k2.

To calculate the slope k of any line, you have to change the equation to y=kx+b

For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))

For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)

Now you can get the answer: The two lines neither parallel nor perpendicular.

6 0
3 years ago
help!! Katherine O’Donnell obtain a personal loan of $3000 at 14% for 24 months. The monthly payment is $144. What is the intere
lina2011 [118]
3000*0.14*24=??? Then uuu add the 144 to your answer to get your answer
8 0
3 years ago
There are 4 lunch choices in a school cafeteria: Salad, Pizza, Spaghetti, and Sub Sandwiches. The percentage of students that ch
Mademuasel [1]
Sorry its sideways, but I hope this helped!

4 0
3 years ago
Read 2 more answers
Solve for a and b<br> (6a-3)=(7b-10)
Free_Kalibri [48]

Answer:

for A=\frac{7b-7}{6} and for B=\frac{6a+7}{7}

Step-by-step explanation:

For A

\left(6a-3\right)=\left(7b-10\right)

6a-3+3=7b-10+3

6a=7b-7

\frac{6a}{6}=\frac{7b}{6}-\frac{7}{6}

a=\frac{7b-7}{6}

For B

\left(6a-3\right)=\left(7b-10\right)

7b-10=\left(6a-3\right)

7b-10=6a-3

7b-10+10=6a-3+10

7b=6a+7

\frac{7b}{7}=\frac{6a}{7}+\frac{7}{7}

b=\frac{6a+7}{7}

3 0
3 years ago
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