a triangle has vertices on a coordinate grid at N(2,-6), O(-10,-6), and P(2,7). what's the length in units of NO

Mathematics

1 answer:

kumpel [21]3 years ago

4 0

12 units

|-10| + 2 = 12

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Please help and explain please

butalik [34]

The greatest remainder with 3 is 2, the greatest remainder with 8 is 7, and the greatest remainder with 5 is 4, all because if it was one more then it would not be remaining and it would be without a remainder. Hope this helps!

4 0

3 years ago

Please help on this math problem

Arte-miy333 [17]

Answer:

1680 in^3

Step-by-step explanation:

SO you got the triangle

24*10=240

240/2=120

now we just need to find the area

There is a formula but I think this is easier

So theres a rectangle with a length of 14

So if you think of the triangle as the base, you just need 14 triangles stacked up to make up the volume

So 120*14=1680

So the volume is 1680

6 0

2 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$