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exis [7]
3 years ago
11

Which description represents the expression 5x−9 ? A. 9 is subtracted from the product of 5 and a number B.9 more than the produ

ct of 5 and a number C.9 is subtracted from the sum of 5 and a number D.5 times the difference of a number and 9
Mathematics
2 answers:
notka56 [123]3 years ago
7 0
A. 9 is subtracted from the product of 5 and a number 

is your answer

hope this helps
madam [21]3 years ago
3 0

Answer:


It's A, I took the test.


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Directions: Solve for X. Round to the nearest tenth. . 12 54​
AfilCa [17]
12.8 degrees

sin = o/h

sin(x) = 12/54

sin^-1 (12/54)

= 12.8 degrees
3 0
3 years ago
How much interest is earned in one year on 5,000 at an interest rate of 3%?
Sergio039 [100]
150 is the amount of interest earned for one year because the formula of PRT is, in this case 5000 times 0.03 times one which gets you the answer of 150.
8 0
3 years ago
2(x + 4) - 5 = 3x + 3
OverLord2011 [107]

Answer:

x=0

Step-by-step explanation:

2(x+4)- 5 = 3x+3

Distribute

2x+8-5 = 3x+3

Subtract x values

8-5 = x+3

3 = x+3

Final Subtraction

x = 0

3 0
3 years ago
Read 2 more answers
Can someone please help will give brainliest Links will be banned
Korvikt [17]

Answer:

Starting is 10 going up by 5x

Step-by-step explanation:

When you look at a graph there is a y and x axis's. 10 is on the y axis and its going up by 5x.

6 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}

is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

b. Find the marginal joint density of X and Y by integrating the joint density with respect to z:

f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

Then

\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

7 0
3 years ago
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