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3 years ago

Are the expressions -0.5(3x + 5) and -1.5x + 2.5 equivalent? Explain why or why not.

1 answer:

5 0

No, they are not equivalent because if you distribute the -0.5 in the expression -0.5(3x+5) you will get -1.5x-2.5 which is not the same as -1.5+2.5

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CAN ANYONE PLS HELP ME I'VE BEEN STUCK ON THIS FOREVER AND WENT ON PEER ANSWER QUESTIONCOVE AND NOW BRAINLY

Bezzdna [24]

Comment
There are 3 ways you could solve this
1. You could graph it.
2. You could equate the line to the quadratic
3. You could just put the x value of the points into both equations until you get the same y value. It sometimes is the only way to solve a multiple choice math question. I do the first two ways.

Step One
Graph the two equations.

The graph is below.

Step 2
From the graph determine the answers.
There are two points where the graphs coincide
Check out D

Step 3
Equate the two equations. The y values must be the same.
6x + 6 = -x^2 + 5x + 6

Step 4
Solve

6x + 6 = - x^2 + 5x + 6 The 6s cancel which is very handy.
6x = -x^2 + 5x Pull the 2 terms on the left over to the right.
6x - 5x = -x^2
x = - x^2
x^2 + x = -x^2 + x^2
x^2 + x = 0 Factor
x(x + 1) = 0

That means that
x = 0
or
x + 1 = 0
x = - 1

Step 3
Find the ys
y = 6x + 6
if x = -1
y = 6(-1) + 6
y = -6 + 6
y = 0

One of the answers is
(-1,0) <<<<<<<< Answer

Now for the other one
y = 6x + 6
x = 0
y = 6(0) + 6
y = 6

The other point is (0,6) answer <<<<<<<

D <<<<<< Total answer

7 0

3 years ago

Use the law of sines to find the length of side c (answer as soon as possible)

Serggg [28]

Answer:

Step-by-step explanation:

Using the law of sines in ΔABC, then

$\frac{c}{sinC}$ = $\frac{a}{sinA}$

Substituting in values gives

$\frac{c}{sin31.6}$ = $\frac{25}{sin38}$ ( cross- multiply )

c × sin38° = 25 × sin31.6° ( divide both sides by sin38° )

c = $\frac{25(sin31.6)}{sin38}$ ≈ 21.28 → D

7 0

4 years ago

What times what equals 150 but also what plus what equals 31

Komok [63]

3*50=150 and 20+11=31

3 0

3 years ago

One leg of a right triangle is more than 3 more inches than the shorter leg. The hypotenuse is 15 inches. What are the lengths o

Deffense [45]

Answer:

1. 9 inches, 12 inches and 15 inches

2. 54 square inches

Step-by-step explanation:

1. The first part of this question would lead to a quadratic equation. Let the shorter leg be represented by x.

shorter leg = x

other leg = x + 3

hypotenuse = 15 inches

Applying the Pythagoras theorem, we have;

$/15/^{2}$ = $/x/^{2}$ + $/x+3/^{2}$

225 = $x^{2}$ + $(x+3)^{2}$

225 = $x^{2}$ + $x^{2}$ + 6x + 9

= 2 $x^{2}$ + 6x + 9

2 $x^{2}$ + 6x + 9 - 225 = 0

2 $x^{2}$ + 6x - 216 = 0

divide through by 2 to have

$x^{2}$ + 3x - 108 = 0

From the quadratic formula;

x = (-b ± $\sqrt{b^{2}-4ac }$ ) ÷ 2a

but, a = 1, b = 3, c = -108

x = (-3 ± $\sqrt{(3)^{2}-4(1)(-108)}$ ) ÷ 2

= (-3 ± $\sqrt{441}$ ) ÷ 2

= (-3 ± 21) ÷ 2

Thus,

x = (-3 + 21) ÷ 2 OR x = (-3 - 21) ÷ 2

x = 9 OR x = -12

So that, x = 9 inches

The shorter leg is 9 inches, and the other leg is 12 inches.

2. The area of the triangle can be determined by applying Heron's formula:

A = $\sqrt{s(s-a)(s-b)(s-c)}$

where s is the average value of the sum of the three sides a, b, and c.

Let, a = 9, b = 12 and c = 15

s = $\frac{a +b+c}{2}$

= $\frac{(9+12+15}{2}$

= 18

A = $\sqrt{18(18-9)(18-12)(18-15)}$

= $\sqrt{18*9*6*3}$

= $\sqrt{2916}$

A = 54

Area of the triangle is 54 square inches.

4 0

3 years ago

Nine and thirty six hundredths with a decimal point

Vilka [71]

The answer is 9.36. There is nine which equals 9, "and" means point or the decimal point and six means 6 and "hundredths" represents the position of the number which is in the hundredths place. When you count numbers to the right, you add "ths" so if there wasn't a 6 and just a 3, then it would be tenths.

8 0

4 years ago

Read 2 more answers