Answer:
A = 307.9 sq/cm
Step-by-step explanation:
Find the radius of the semi-circle
diameter + half the circumference = 72 cm
2r + pi*r = 72
r(2+pi) = 72
r = 72%2F%28%282%2Bpi%29%29
r = 14
:
what will be the area of that semicircle?
A =1%2F2*pi%2A14%5E2
A = 307.9 sq/cm
Answer
(x-1) (x-4)
Step-by-step explanation:
I did this not long ago in class so that's the answer
Answer:
Step-by-step explanation:
Given that a statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years.
Mean = 78 and std dev =10
Next time, sample size n was reduced to 25
For smaller sample size the mean was found to be = 83
The teacher wanted to know if teaching a smaller class was more effective and students performed better
ie comparison of two means of two samples should be done with different sample sizes but same teacher.
Hence hypothesis should be:
where x denotes the I sample and Y the second with 25 students.
Answer: The answer is Yes.
Step-by-step explanation: Given that Michael estimated his mass and found it to be 8 kilograms. It may sound awkward to us, but its true. Because when we measure our weight by the weight machine it gives us the product of our actual mass and the acceleration due to gravity.
From second law of motion, we have
Weight = mass × acceleration due to gravity.
That is, W = m × 9.8 m/sec².
The unit of mass is kilogram and 1 kg m/sec² = 1 Newton. Therefore, the unit of the weight we generally measure is Newton (N), not kilogram. Here is what we make mistake usually.
Thus, if Michael' mass is 8 kg, then his weight will be
W = 8 × 9.8 kg m/sec² = 78.4 N, which is normal weight of a person.
Thus, his estimation is perfectly OK.
Answer:
I'm pretty sure its C but some please correct me if I'm wrong.
