Answer:
just add the equation and solve it then the value of X could be found then put the value of X and the value of y can be found. Just like in the below
Step-by-step explanation:
X+y=3 ------------ equation 1
4x-y=7 ------------ equation 2
adding equation 1 and 2
X+y=3
+ 4x-y=7
-----------------
5x = 10
X = 10/5
X = 2
putting the value of X in equation 1
or, 2+y=3
or, y = 3-2
Thus, y = 1
Answer:
x=60
Step-by-step explanation:
right angle is 90 degrees +30 degrees equals 120 so 180-120 gives you 60 degrees
Answer:
16/52, or 4/13.
Step-by-step explanation:
First, since we know that the question is asking for the probability of a club <u>or</u> a jack, we know that we have to add the two probabilities. The first probability is that of picking a club, which is 13/52. The probability of picking a jack (be sure not to overlap; don't double count the jack of clubs) is 3/52. Adding these two gives us 13/52+3/52=16/52, which simplifies to 4/13.
Answer:
Both the stock have the same expected return.
Step-by-step explanation:
In year 1 the return earned by stocks A and B are:
Stock A = 2% return
Stock B = 9% return
In year 2 the return earned by stocks A and B are:
Stock A = 18% return
Stock B = 11% return
Compute the expected return for stock A as follows:

Compute the expected return for stock B as follows:

Thus, both the stock have the same expected return.
The equation of the line is 
<u>Step-by-step explanation:</u>
- The line passes through the point (2,-4).
- The line has the slope of 3/5.
To find the equation of the line passing through a point and given its slope, the slope-intercept form is used to find its equation.
<u>The equation of the line when a point and slope is given :</u>
⇒ 
where,
- m is the slope of the line.
- (x1,y1) is the point (2.-4) in which the line passes through.
Therefore, the equation of the line can be framed by,
⇒ 
⇒ 
Take the denominator 5 to the left side of the equation.
⇒ 
Now, multiply the number outside the bracket to each term inside the bracket.
⇒ 
⇒ 
Divide by 5 on both sides of the equation,
⇒ 
Therefore, the equation of the line is 