Line 1--------- >(0,2) (1,-1)
y=mx+b m=(-1-2)/(1-0)=-3
2=(-3)*(0)+b----- > b=2
y1=-3x+2Line 2--------- >(0,-1) (2,2)
y=mx+b m=(2+1)/(2-0)=3/2
-1=(3/2)*(0)+b----- > b=-1
y2=(3/2)x-1
<span>using a graphic tool
see attached figure</span>
the best estimate solution for the system is <span>
(1, 1)
because </span>is the only one within the range of the x axis (-5,5) and the y axis (-5,5)
I would have to say that i think the answer is D. hope this helps
Answer:
Determinant are special number that can only be defined for square matrices.
Step-by-step explanation:
Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.
How to find determinant
For a 2×2 matrix
For a 3×3 matrix
we first decompose it to 2×2
Example
Find the values of λ for which the determinant is zero
Equating the determinant to zero
s = * (1 ±5 )
s = 1.61 or -0.61
64 oz / 12 oz = between 5 and 6 cans
Answer:
-27/5
Step-by-step explanation:
[x*4 + 3(x-1)]\12=2+x
4x+ 3x -3 =12(2+x)
7x -3 =24 +12x
7x-12x =24 +3
-5x =27
x = (-27/5)