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jonny [76]
2 years ago
15

Use a proportion to find the length of side x for the pair of similar figures

Mathematics
1 answer:
kogti [31]2 years ago
6 0

Answer:

30.8

Step-by-step explanation:

1. Write the ratio for the smaller triangle as 14/10 and the ratio for the larger triangle as x/22.

2. Set the ratios equal to each other.

14/10 = x/22

3. Cross multiply and solve for x.

14 x 22 = 308

10 x x = 10x

4. Divide by 10

x = 30.8

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There least common factor would be 5 since they are all divisible by 5.
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Help, please in this problem
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Answer:

x=9.768

y=6.972

Step-by-step explanation:

For this problem we have to use the trig relationships of cos and sin to figure out the lengths. Cos is equal to adjacent/hypotenuse so we can set it as x/r=.814 and since r is equal to 12 we can do 12 times .814 to get x.

We do a similar process for sin but sin is equal to opposite/hypotenuse so we can set up the equation y/r=.581 and we simply multiply both sides by 12 to get 12*.581 to get y.

Also for future reference adjacent and hypotenuse are based on the angle at use, since ∅ is on the bottom left x is the adjacent side and y is the opposite side.

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2 years ago
Determine the slope of a line that is perpendicular to the line 2y = 3x – 6.
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Step-by-step explanation:

4 0
2 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
2 years ago
How you do this expression
katrin2010 [14]
You are using the distributive property so you will multiply all the numbers in the parentheses by 5. So the end expression would be 30m+20n-15p
4 0
3 years ago
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