Solve the following system using elimination:
{3 a + 4 b = 2 | (equation 1)
{5 a + 9 b = 1 | (equation 2)
Swap equation 1 with equation 2:
{5 a + 9 b = 1 | (equation 1)
{3 a + 4 b = 2 | (equation 2)
Subtract 3/5 × (equation 1) from equation 2:
{5 a + 9 b = 1 | (equation 1)
{0 a - (7 b)/5 = 7/5 | (equation 2)
Multiply equation 2 by 5/7:
{5 a + 9 b = 1 | (equation 1)
{0 a - b = 1 | (equation 2)
Multiply equation 2 by -1:
{5 a + 9 b = 1 | (equation 1)
{0 a+b = -1 | (equation 2)
Subtract 9 × (equation 2) from equation 1:
{5 a+0 b = 10 | (equation 1)
{0 a+b = -1 | (equation 2)
Divide equation 1 by 5:
{a+0 b = 2 | (equation 1)
{0 a+b = -1 | (equation 2)
Collect results:
Answer: {a = 2
{b = -1
Answer: the answer to 1 is 2
Step-by-step explanation:
A fifth of 25 students would be 5 (25/5).
Four-fifths of the students would be the result of (25/5) multiplied by 4.
(25/5)*4
5*4
= 20; 20 students like football.
The lowest term of 836/54 is 418/27!
