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3 years ago

12

After you withdraw $35 from your checking account, the new balance is $260. Which equation shows the equation that could be used

to find the balance on your account before the withdrawal?

1 answer:

777dan777 [17]3 years ago

4 0

I think that it’s $260+$35=$295

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Fudgin [204]

Answer:

100.05

Step-by-step explanation:

V=πr^2h /3

kπ=π5a^2*12a/3

k=100.05

4 0

3 years ago

What is 9 - 2x = 35?

frozen [14]

Answer:

x = -13

Step-by-step explanation:

9 - 2x = 35

Subtract 9 from both sides of the equation:

9 - 2x - 9 = 35 - 9

-2x = 26

Divide both sides of the equation by -2:

$\frac{-2x}{-2} = \frac{26}{-2}$

x= -13

3 0

3 years ago

The two triangles illustrated below are similar. What are the values of x and y?

Makovka662 [10]

Answer: A
Explanation: using the common ratio we can solve this. 24:8 = x:4
24 divided by 8 is 3.
Therefore x divided by 4 should be 3 too.
4 multiplied by 3 is 12, so x = 12.
For y:
When triangles are similar, the angles are always the same. So y is simply 40 degrees.

4 0

3 years ago

A gardener is planting two types of trees: Type A is 7 feet tall and grows at a rate of 10 inches per year. Type B is 4 feet tal

trasher [3.6K]

Answer:

9 years

Step-by-step explanation:

Let the the number of years in which height of both the type of tree is same be n years

Initial length of type A tree = 7 feet

As rate of growth is given in inches to maintain uniformity of measuring unit lets convert feet to inches

1 feet = 12 inches

thus 7 feet = 12*7 inches = 84 inches.

length of type A tree in inches = 84 inches

Rate of growth of type A tree = 10 inches per year

Thus, actual growth of type a tree in "n" years = 10*n = 10n

Total height of type A tree in n years = initial length + growth in n years

= 84 inches+ 10n inches (1)

____________________________________________________

For type B

Initial length of type B tree = 4 feet

As rate of growth is given in inches to maintain uniformity of measuring unit lets convert feet to inches

1 feet = 12 inches

thus 4 feet = 12*4 inches = 48 inches.

length of type B tree in inches = 48 inches

Rate of growth of type A tree = 14 inches per year

Thus, actual growth of type a tree in "n" years = 14*n = 14n

Total height of type b tree in n years = initial length + growth in n years

= 48 inches+ 14n inches (2)

_________________________________

Given condition that after n years height of both the type of tree is same

equation 1 should be equal to equation 2

84 inches+ 10n inches = 48 inches+ 14n inches

=>84 inches - 48 inches = 14n inches - 10n inches

=> 36 inches = 4n inches

=> 36 = 4n

=> n = 36/4 = 9

Thus, after 9 years both of their height will be same which be equal to

84+10*9 = 84 + 90 = 174 inches.

5 0

3 years ago

A company produces a certain product, and each unit of this product may have 3 different types of defects. Let Di, D2,Ds represe

Stella [2.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) 0.88

b) 0.02

c) 0.01

d) 0.99

Step-by-step explanation:

Step one: State the given parameters

$P(D_{1} ) = 0.12$ $P(D_{2} ) = 0.07$

$P(D_{3} ) = 0.05$ $P (D_{1} U D_{2} ) = 0.13$

$P(D_{1}n D_{2}n D_{3}) = 0.01$ $P(D_{1} U D_{3}) = 0.14$

Step 2 : Obtain the probability that a unit does not have a type 1 defect

$P(\frac{}{D_{1} })$ = $1 -P(D_{1} )$

= $1 - 0.12$

= 0.88

Step 3 : Obtain the probability that a unit has both type 2 and 3 defect?

The probability of the unit having both type 2 and type 3 defect is denoted as $P(D_{2} n D_{3} )$

This is calculated as

$P(D_{2}n D_{3}) =P(D_{2} ) + P(D_{3}) - P(D_{2} U D_{3})\\\\ = 0.07 + 0,05 - 0.13$

= 0.02

Therefore P(D_{2} n D_{3} ) = 0.02

Step 4 : Obtain the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect

Let $P(\frac{}{D_{1}} n D_{2} n D_{3} )$ denote the probability that the unit has both a type 2 and type 3 ,but not a type 1 defect.

This can be calculated as follows :

$P(\frac{}{D_{1}} n D_{2} n D_{3} ) = P(D_{2} n D_{3}) - P(D_{1} n D_{2}nD_{3})$

= 0.02 - 0.01

= 0.01

Step 4 : Obtain the probability that a unit has at most two defects

P(at most 2 defects) = 1 - P(all three defects)

= $1- P(D_{1} n D_{2}nD_{3})$

= 1 - 0.01

= 0.99

7 0

3 years ago