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ira [324]
2 years ago
6

Hesperia Community center is buying new seating for their building. They want to purchase a combination of stools and chairs. St

ool cost $15 and chairs cost $25. The center cannot spend more than 1500. Which inequality represents all possible combinations of s stools and c chairs? A. 15s + 25c < 1500 B. 15c + 25s > 1500 C. 15c + 25s < 1500 D. 15s + 25c < 1500​
Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
7 0

Answer:

I just finished taking the test and the answer is 15s + 25c ≤ 1500

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Someone help me please
kherson [118]

Answer:

I will just choosé the second one

Because it is possible to compare sizes In one triangle rather than comparing with another one which we don't reàlly know of its sizes.

4 0
2 years ago
2 3/4 + 12 6/8 = answer
svet-max [94.6K]

Answer:

15 1/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The scale factor from S to M is 3/2 What is the scale factor from M to S
natita [175]

we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

<h3></h3><h3>What is the scale factor from M to S?</h3>

Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.

So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:

M = S*K

If that scale factor is 3/2, then we have the case of the problem:

M = (3/2)*S

We can isolate S in the above relation:

(2/3)*M = S

Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.

Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

If you want to learn more about scale factors:

brainly.com/question/25722260

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3 0
1 year ago
Use an induction proof to prove this statement:<br> For n≥1, 4^n+5 is divisible by 3.
Tpy6a [65]

Answer:

See below

Step-by-step explanation:

We shall prove that for all n\in\mathbb{N},3|(4^n+5). This tells us that 3 divides 4^n+5 with a remainder of zero.

If we let n=1, then we have 4^{1}+5=9, and evidently, 9|3.

Assume that 4^n+5 is divisible by 3 for n=k, k\in\mathbb{N}. Then, by this assumption, 3|(4^n+5)\Rightarrow4^k+5=3m,\: m\in\mathbb{Z}.

Now, let n=k+1. Then:

4^{k+1}+5=4^k\cdot4+5\\=4^k(3+1)+5\\=3\cdot4^k+4^k+5\\=3\cdot4^k+3m\\=3(4^k+m)

Since 3|(4^k+m), we may conclude, by the axiom of induction, that the property holds for all n\in\mathbb{N}.

3 0
2 years ago
Solve the system of equations <br><br> y=2x+1<br> y=x^2+2x-8
Lemur [1.5K]

Answer:

(3,7) and (-3,-5)

Step-by-step explanation:

To solve the system of equations, graph both functions. The (x,y) point(s) where the functions intersect is the solution(s).

See attached picture.

7 0
3 years ago
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