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Luba_88 [7]
3 years ago
14

Solve the inequality. 2(4x – 3)-3(3x) + + 5x?​

Mathematics
1 answer:
sashaice [31]3 years ago
3 0

Answer:

2 (2 x - 3)

Step-by-step explanation:

Simplify the following:

2 (4 x - 3) - 3×3 x + 5 x

-3×3 = -9:

2 (4 x - 3) + -9 x + 5 x

Grouping like terms, 2 (4 x - 3) - 9 x + 5 x = 2 (4 x - 3) + (5 x - 9 x):

2 (4 x - 3) + (5 x - 9 x)

5 x - 9 x = -4 x:

2 (4 x - 3) + -4 x

2 (4 x - 3) = 8 x - 6:

8 x - 6 - 4 x

Grouping like terms, 8 x - 4 x - 6 = (8 x - 4 x) - 6:

(8 x - 4 x) - 6

8 x - 4 x = 4 x:

4 x - 6

Factor 2 out of 4 x - 6:

Answer: 2 (2 x - 3)

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2 years ago
The probability that a person in the United States has type B​+ blood is 10%. Four un-related people in the United States are se
marysya [2.9K]

Answer:

a. 0.0001

b. 0.6561

c. 0.3439

d. B. The event in part​ (a) is unusual because its probability is less than or equal to 0.05.

Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood  = 0.10 x 0.10x 0.10x0.10

                                                                                       = 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90                                                                        

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

#The probability that at least one of the four have B+ blood = 1 -  Probability that none have B+ blood type

=1-0.6561=0.3439

Therefore,the probability that at least one of the four has type B+ blood is 0.3439

d. An event is considered unusual if the probability of the event is small or less than 0.05 . We note that event a is the only small probabilty and is less than 0.05.

-a is thus considered unusual(the rest are all usual events)

                                                                                                                 

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How to write six billion sixty- seven million four hundred four thousand thirteen and nineteen thousandths in standard form?
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Standard for would be 6,670,404,013.19
8 0
3 years ago
Can someone answer this for me?
Sophie [7]

Answer:

D 26

Step-by-step explanation:

154+154=308

308-360=52

52 divided by 2

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3 years ago
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