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3 years ago

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Lines l and m are parallel. Find m∠3 if m∠5 = 38 and m∠6 = 62.

1 answer:

saul85 [17]3 years ago

5 0

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a farmer planted 1/8 of his land with beans 1/4 with corn 3/10 with wheat and left the rest unplanted what percentage of his lan

Verizon [17]

Answer:

30.25% percent of land is unplanted

8 0

3 years ago

20x^2-19x+3 divided by 5x-1

BabaBlast [244]

(20x^2-19x+3)/5x-1
(400x-19x+3)/5x-1
(381x+3)/5x-1
381x/5x-1 + 3/5x-1
(381/5-381) + (3/5x -3)
(76.2-381) + (3/5x -3)
304.8 + 3/5x-3
101.8 +3/5x

That's what I got. I'm not too sure if it helps though.

3 0

3 years ago

Read 2 more answers

Tell whether the triangle with the given side lengths is a right triangle

Andreas93 [3]

Answer:

not a right triangle

Step-by-step explanation:

The Pythagorean Theorem states that If a triangle is a right triangle,

the hypotenuse^2 will equal to shorter^2 + longer^2

hypotenuse = 18, shorter side = 4, longer side = 17

18^2 = 4^2 + 17^2

324 = 16 + 289

324 = 305

That is false, therefore the triangle is not a right triangle

6 0

3 years ago

Read 2 more answers

One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago

Find the equation of a line with slope 1/2 through the point (10,12)

mihalych1998 [28]

Answer:

$x-2y+14=0$

Step-by-step explanation:

$Slope \:( m) =\frac{1}{2}$

$(x_1 \:y_1) =(10, \:12)$

Equation of line in point slope form is given as:

$y-y_1 =m(x-x_1)$

Plugging the values of m and $(x_1 \:y_1)$ , we find:

$y-12=\frac{1}{2} (x-10)$

$2y-24=x-10$

$0=x-10-2y+24$

$x-2y+14=0$

This is the required equation of line.

5 0

3 years ago