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Eddi Din [679]
3 years ago
13

Given that 9=110 8=70 an p is parallel to q did I fill this out right?

Mathematics
2 answers:
julsineya [31]3 years ago
8 0

Answer:

yes i think so it looks quite accurate

natima [27]3 years ago
4 0

Answer:

This does look like the right answer. I think you filled it out right

Step-by-step explanation:

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roberto needs to convert the equation 3x + y = -5 into slope-intercept form. why is able to add or subtract the variable term fr
dimulka [17.4K]
3x + y = -5

-3x + 3x + y = -3x - 5

y = -3x - 5
7 0
3 years ago
SOVing Problems With Right Triangles: Mastery Test
Serhud [2]

Answer:

13.86 ft

Step-by-step explanation:

This can be represented by a right angled triangle with a hypotenuse of 16 feet and an angle of 60° between the hypotenuse side and the adjacent side.

The height of the pole is the side opposite to the angle 60°.

The trigonometric function states that for a right angled triangle:

sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite/ adjacent

To find the height of the flagpole, we use:

sin(60) = height / 16

height = 16 * sin(60)

height = 13.86 ft

The person with the incorrect reasoning for the height of the flagpole is  Charlie when he should have utilized the  sin function. Because he incorrectly selected the  function.

7 0
3 years ago
Express in the form 1:n<br> Give n as a fully simplified fraction.<br><br> 12:2
statuscvo [17]

Answer:

divide 12

12/12 : 2/12

1 : 2/12

1 : 1/6

n=1/6

7 0
3 years ago
Help with Frations please
ollegr [7]
2 i think. it says one of each doesn't it?
7 0
3 years ago
Fred is running on the school track. He can run 10 3 4 laps in 4 5 of an hour. How many laps can Fred run in one hour?
Triss [41]

Answer:

13\frac{7}{16} laps can Fred run in one hour.

Step-by-step explanation:

Given Statement: Fred is running on the school track. He can run 10\frac{3}{4}  laps in \frac{4}{5}  of an hour.

Unit rate are expressed as a quantity of 1, such as 3 feet per second or 7 miles per hour, they are called unit rates

From the given condition we have;

In \frac{4}{5} he can run \frac{43}{4} laps

Unit rate per hour = \frac{\frac{43}{4} }{\frac{4}{5} }

                              =\frac{43}{4} \times \frac{5}{4} = \frac{215}{16} laps

Therefore, Fred can run in one hour is, 13\frac{7}{16} laps.

3 0
3 years ago
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