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2 years ago

Point A has coordinates (-5, 3). If point (1,6) is

Mathematics

1 answer:

gtnhenbr [62]2 years ago

8 0

Answer:

$(3, 7)$

Step-by-step explanation:

(4/3)P -(4/3)A + A = B . . . . . . add A

(4P -A)/3 = B . . . . . . . . . . . . . simplify

Then the coordinates of point B are ...

B = (4(1, 6) -(-5, 3))/3 = (9, 21)/3

B = (3, 7)

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DILATION GEOMETRY QUESTION

Cloud [144]

Answer:

A'B'C'D' was dilated by 4

Step-by-step explanation:

The distance from B' to C' is 1.

The distance from B to C is 4.

4/1=4

4 0

2 years ago

Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum

const2013 [10]

Answer: The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

$S=\sum_{i=1}^{\infty}15(4)^{i-1}.$

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, $\sum_{i=1}^{\infty}a_i$ is an infinite series, with complex coefficients $a_i$ and we consider the following limit:

$L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.$

Then, the series will be convergent if L < 1 and divergent if L > 1.

For the given series, we have

$a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.$

So, the limit is given by

$L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.$

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

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3 years ago

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Use >,<,=.<br> 0.94___0.49

uranmaximum [27]

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3 years ago

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3 years ago

Free points hope this helps you a little!<br> luv you!

nikdorinn [45]

Answer:

thx chief

Step-by-step explanation:

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3 years ago

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