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ladessa [460]
2 years ago
12

HELP!! I WILL GIVE BRAINLIEST

Mathematics
1 answer:
FrozenT [24]2 years ago
3 0

Number one: Just plot down on the number like the numbers you have. Just took the test for this.

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Determine whether the triangle is a right triangle. Explain your reasoning. If it is not a right triangle, determine whether it
Alinara [238K]

Answer:

If it's Jose, Brad, and Ed it's an acute triangle, it has no 90 degree angle, if it's Jose, James, and Malcolm it is a right triangle because the line to Jose and Malcolm is straight I think not sure how to explain

Step-by-step explanation:

5 0
2 years ago
4x^2=27x+40<br> Solve by factoring
worty [1.4K]

Answer: hewo, there! your answer is below

x= -5/4

or x= 8

Step-by-step explanation:

step 1: Subtract 27x+40 from both sides.

4x2−(27x+40)=27x+40−(27x+40)

4x2−27x−40=0

Step 2: Factor left side of equation.

(4x+5)(x−8)=0

Step 3: Set factors equal to 0.

4x+5=0 or x−8=0

hope this helps you

have a great Day

Plz makr branilest

8 0
2 years ago
A widget company produces 25 widgets a day,5 of which are defective.Find the probability of selecting 5 widgets from the 25 prod
MariettaO [177]

Answer:

0.292

Step-by-step explanation:

Combinations can be used to solve the following problem.

We are choosing 5 widgets from 25 = ²⁵C₅

We want to select zero widgets from defective widgets = ⁵C₀

From the 20 non-defective widgets we want to select 5 = ²⁰C₅

So the probability is:

P = ( ⁵C₀ * ²⁰C₅) / ²⁰C₅

P = (1 * 15504) / 53130

= 15504/ 53130

=0.292 ..

7 0
3 years ago
Which is equivalent to 3v8
Tomtit [17]

Answer:

C.

Step-by-step explanation:

= \sqrt[3]{8}^{x}\\

= Since \sqrt[3]{} = ^{1/3}

= So, It becomes :

= 8^{\frac{x}{3}

4 0
3 years ago
Read 2 more answers
Identify the hyperbolas (represented by equations) whose centers are at (2, 1)
weqwewe [10]
When the transverse axis is horizontal, a hyperbola centered at (h,k) has formula (x-h)^2/a^2-(y-k)^2/b^2=1. Plug in h=2, k=1, the formula is (x-2)^2/a^2-(y-1)^2/b^2=1 for some a,b. If the transverse axis is vertical, the formula is (y-h)^2/a^2-(x-k)^2/b^2=1, and (y-2)^2/a^2-(x-1)^2/b^2=1 in our case.
5 0
3 years ago
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