All categories

3 years ago

You deposit $1500 in an account that pays 5% interest compounded yearly. Find

Mathematics

2 answers:

nata0808 [166]3 years ago

7 0

Bdafwhwrsffhfwwfhrgggggkgf

Anna11 [10]3 years ago

3 0

Answer:

1950 is the balance after 6 years

Step-by-step explanation:

multiply 1500 to 0.05 to get the interest amount, then multiply that number by 6 for the 6 years, and then add it back to the 1500 to get 1950

You might be interested in

if the sum of a number and nine is tripled the results is seven less than twice the number. find the number

aliina [53]

Here is the equation you need:

3(x + 9) = 2x - 7

You finish.

6 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

6 ( − 2.1 x − 2 ) + ( 7 x + 5 )

Mariana [72]

Answer: −5.6x −7

Step-by-step explanation:

8 0

3 years ago

School lunches cost ₱35.50 per week. about how much would 15.5 weeks of lunches cost?grade v

Goryan [66]

Answer:

₱ 550.25

Step-by-step explanation:

₱ 35.50 * 15.5 weeks = ₱ 550.25

5 0

3 years ago

Read 2 more answers

For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?

Arlecino [84]

Answer:

For $c=\frac{1}{7}$ the function f(x) is continuous on $(-\infty,\infty)$ .

Step-by-step explanation:

We have the following function

$f(x) = \left\{ \begin{array}{ll} cx^2+5x & \quad x$

For the function f(x) to be continuous on $(-\infty,\infty)$ it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

$\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x)$ ,

which holds if and only if

$c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6$

namely if $c=\frac{1}{7}$ .

6 0

3 years ago