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Mathematics

2 answers:

prohojiy [21]2 years ago

8 0

Answer:

B) 48
D) 81
A) 11
B) -81
-246
C) 5
A) 19 9/25
D) 11
A) 48
D) m-c/-b =a

Step-by-step explanation:

comment if you want the explanation, but you said you wanted it fast and it would take me like 10 minutes to right it all out

vovangra [49]2 years ago

3 0

Answer:

1)b.48 2)d.81 3)a.11 4)b.–81 5)–246 c.5ft a.19 9/25 in² d.11 mi/h a.48 C.a=m–c/–b

Step-by-step explanation:

4²+(4×2³)=16+(4×8)=16+32=48

(–3)⁴=3²×3²=9×9=81

–2n²+5n+9 (n=2)

–2(2²)+5(2)+9=–2×4+5×2+9=–8+10+9=11

3x³ (x=–3)

3(–3)³=3×–27=–81

4r²–2s³ (r=1 s=5)

4×1–2×125=4–250=–246

A=½bh. ½b=A/h. b=2A/h

then b=(2×30)÷12=5ft

area of a square=s×s=

$4 \times \frac{2}{5} \times 4 \times \frac{2}{5} = \frac{22}{5} \times \frac{22}{5} = \frac{484}{25} = 19 \times \frac{9}{25} {in}^{2}$

d=rt then r=d/t

then r=15.4÷1.4=11 mi/h

(–h–3j)²/h (h=3, j=–5)

(–3–3×–5)²÷3=(12)²÷3=144÷3=48

m=c–ab m–c=–ab m–c/–b=a

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What is the equation of the asymptote of the graph of y=3(4^x) A. x=4 B. x=0 C. y=3 D. y=0

kompoz [17]

The asymptote cannot be x= because x can be any number. If you think about it, you can take a number to any exponent.
If x is a positive exponent, y is positive.
If x is a nevative exponent, y decreases, but is still positive. This is because a number to a negative exponent equals 1 over the number to the positive exponent. Thus, it is smaller, but still positive.
If x is 0, y is positive again because anything to the zero is positive 1.
There is no way y could be less than or equal to zero. So, there is an asymptote at y=0.
Also, set the equation equal to 0 and solve. You should end up with 4^x=0. Since no exponenent can make a number zero, this isn't possible, so y cannot equal zero.
Here is the graph for a visual: