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Sindrei [870]
3 years ago
8

What is the area of this parallelogram?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
6 0
Area of a parallelogram is base x height
base is 6+5=11
height = 12
11*12 = 132cm square


or
there are 2 triangles and 1 rectangle
the triangles measure the same thing
the formula for the area of a triangle is 1/2bh
1/2*6*12 = 36
area of rectangle
is length x breadth
5*12 = 60
area of whole parallelogram = 60+36+36= 132cm square

either ways you get the same answer
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4 0
4 years ago
Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t
Yanka [14]

Answer:

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

\hat p=\frac{X}{n} estimated proportion of  scissors selected for each friend

p_o=\frac{1}{3}=0.333 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:  

Null hypothesis:p\geq 0.333  

Alternative hypothesis:p < 0.333  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Friend A

\hat p_A= \frac{100}{400}=0.25

z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47  

Friend B

\hat p_B= \frac{20}{120}=0.167

z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80  

Friend C

\hat p_C= \frac{65}{300}=0.217

z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17  

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

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Step-by-step explanation:

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