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3 years ago

Please help and show work

Mathematics

1 answer:

weqwewe [10]3 years ago

7 0

Because corresponding parts in a similar polygon is in proportion, 18/12=x/5

12x=90

4x=30

2x=15

x=15/2

Done!

If you have any more questions about this problem just comment and I will answer it for you, also I would really really appreciate it if you give me brainlliest!

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Solve: (x + 5)^2 + 15 = 64

ch4aika [34]

(x+5)^2 = 49;
Then x + 5 = 7 or x + 5 = -7 ;
Finally, x = 2 or x = -12.

5 0

4 years ago

The square root of 36y^3 =

Aleks04 [339]

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3 years ago

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4 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. x

miskamm [114]

Answer:

$\frac{784}{15} \pi$

Step-by-step explanation:

According to the given situation, the calculation of volume of the solid is shown below:-

Here we will consider the curves that is

$x = 7y^2, x = 7$

Now, rotating the line for the line x which is equals to 7

$7y^2 = 7\\\\y^2 = 1\\\\ y = \pm1$

So, the inner radio is

7 - 7 = 0

and the outer radius is

$7y^2 - 7\\\\ = 7(y^2 - 1)$

Now, the area of cross section is

$A(y) = \pi(7(y^2 - 1))^2\\\\ = 49\pi(y^4 - 2y^2 + 1)$

The volume is

$V = \int\limits^1_{-1} A(y)dy$

now we will put the values into the above formula

$= \int\limits^1_{-1} 49\pi(y^4 - 2y^2 + 1)dy\\\\ = 49\pi(\frac{y^5}{5} - \frac{2y^3}{3} + y)^{-1}\\\\ = 49\pi(\frac{1}{5} - \frac{2}{3} + 1 + \frac{1}{5} - \frac{2}{3} + 1)\\\\ = 49\pi(2 + \frac{2}{5} - \frac{4}{3} )\\\\ = 49\pi(\frac{30+6-20}{15} )\\\\ = \frac{49\pi}{15} (16)$