Answer: No
Step-by-step explanation:
Replace x for 5 and -7 separately.
A school is 16km due west of a school q.What is the bearing of q from p?
1 answer:
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
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3a + 4bc - d = 5a - 8j
<em><u>Add d to both sides.</u></em>
3a + 4bc = 5a - 8j + d
<em><u>Subtract 4bc from each side.</u></em>
3a = 5a - 8j + d - 4bc
<em><u>Subtract 5a from both sides.</u></em>
-2a = -8j + d - 4bc
Divide both sides by -2
a =
Factor the trinomial
by the box method.
The multiplication gives -24y^2. Now we need to find two factor that gives 5x. It should be creal that this factor are 8y and -3y. Then:
Now we find the common factor for each column and row:
Therefore:
