Reducing calorie intake is insufficient for a person to loose weight.
If some were to reduce calories, it would cause your stomach to produce more fat cells. It is like you are starving yourself and your stomachs way to save you if producing more fat cells.
Ok, colour blindness and blood type are independently assorting traits, that means that having one does not affect having the other, the question even tells you that the traits are on different chromosomes.
<span>To answer your question we'll have to calculate the probability of both traits in the child and then multiply them together to get the overall probability of both being present in the child. </span>
<span>Let's start with blood type: there are four types of blood type: AB, A, B and O. Blood type is determined by what protein each chromosome codes for: so if one chromosome is I^A and codes for A type protein, while the other is I^B and codes for B type protein, then the overall blood type will be AB. O blood type is recessive, it doesn't code for any protein at all and is given the symbol i. </span>
<span>Since both parents are type A and their first child is type O, you know that both parents are heterozygous for blood type A, meaning that one chromosome they have is I^A and the other is type or or i. For a child to be blood type O, each parent has to give their type O chromosome to the child. There is a 1/2 chance that one parent will give the recessive O chromosome, so for both parents to give their recessive allele the probability is 1/2 * 1/2 = 1/4 </span>
<span>Colour blindness is an X-linked condition, that means that women can be carriers but not manifest the colour blindness because they have one "good" X chromosome which masks the recessive colourblindness gene on the other X. The father cannot have a colourblindness gene or else he'd be colourblind himself, since he's only got 1 X-chromosome. Because dad has healthy eyesight, any girls he has will have healthy eyesight too, since his X will always be healthy and mask the X from mom if she happens to give the recessive colourblind gene. So the probability that the girl will have normal vision is 1/1. </span>
<span>However, it is not a given that the baby born will be a girl, there's a 50/50 chance that it'll be one or the other sex, so we need to consider the probability involved with the child being a girl. this probability is 1/2. </span>
<span>So now we multiply all our probabilities together to calculate what the chances of a normal visioned, type O blood typed girl is: </span>
<span>Normal vision (1) * blood type O (1/4) * girl baby (1/2) = 1/8 </span>
<span>So your probability is 1/8! </span>
<span>Hope this helps :)</span>
In cases of acute renal failure, serum creatinine (SCR) and blood urea nitrogen (BUN) incorrectly predict the glomerular filtration rate (GFR). The possibility exists for serum cystatin C (CYS) to be a more accurate GFR marker. In order to examine the sensitivity of SCR, BUN, and CYS in identifying acute renal failure in mice, this study was conducted.
The conclusion of the study was that In mouse models, CYS can be utilized as an accurate and dependable marker for renal function. In comparison to SCR and BUN, CYS is more sensitive and detects kidney impairment early.
<h3>What is
glomerular filtration rate (GFR)?</h3>
A blood test called a glomerular filtration rate (GFR) measures how well your kidneys are functioning. Glomeruli are little filters found in your kidneys. These filters aid in clearing the blood of waste and extra fluid. How much blood flows through these filters each minute is determined by a GFR test.
To learn more about glomerular filtration rate (GFR) with the help of given link:
brainly.com/question/13064727
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The term pharynx may also be used to describe a differentialed portion of the invertebrate.
