When car B passes car A, they will have traveled the same distance, d.
speed = distance/time
distance = speed * time
Car A travels t time.
Since car B starts an hour later, car B travels t - 1 time.
Car A:
d = st
s = 40t
Car B:
d = st
d = 60(t - 1)
The distance are equal, so
40t = 60(t - 1)
40t = 60t - 60
-20t = -60
t = 3
Car A started at 9 am.
9 am + 3 hours = noon.
Answer: at noon.
Jane final solution is wrong due to the direction of the inequality sign
<h3>Solving linear equation</h3>
Linear equations are equation that has a leading degree of 1
Given the inequality below
-8x + 12x + 2 ≥ 62
Simplify to have
4x + 2 ≥ 62
Subtract 2 from both sides
4x + 2 - 2≥ 62 - 2
4x ≥ 60
Divide both sides by 4
4x/4≥ 60/4
x≥ 15
We can see that jane final solution is wrong due to the direction of the inequality sign
Learn more on inequality here: brainly.com/question/24372553
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You need to first make everything positive:
x^2=36
Then you need to get the square root of each side:
x=6 or -6
Hope this helps :)
Answer:
the slope of the line is the angle at which it slants
Step-by-step explanation: