What are the like terms of 10a+4b+3a-15b

2 answers:

4 0

10a + 3a are like terms because of the a. This equals to 10a

4b-15b are like terms because of the b and this equals to -11b

Expression: 10a-11b

TiliK225 [7]3 years ago

3 0

The like terms in 10a+4b+3a-15b consist of a and b. First, we have to combine like terms.
(10a+3a) + (4b-15b)
solve a and b
13a - 11b. Thus, the like terms in your original expression are 13a and -11b :)

You might be interested in

By what number should -4.125 be divided to get -5.5.

kogti [31]

Answer: 0.75

Step-by-step explanation:

-4.125/-5.5 = 3/4 or 0.75

-4.125/0.75 = -5.5

6 0

3 years ago

7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.

blondinia [14]

$\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill$

$\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}$