Answer:
Option C is right
Step-by-step explanation:
Given are two samples
I group has sample size 90, mean = 9.2 and std dev =0,.37
II group has sample size 70, mean = 7.3 and std dev = 0.58
we find that mean difference i.e. difference between mean hours of sleep between two groups
= 9.2-7.3 = 1.9
Std error for difference = 0.0620
Since sample size is sufficiently large we can use Z critical for 99%
i.e. 2.58
Margin of error =±2.58(0.062)
=0.16
Hence confidence interval 99% for difference in hours of sleep
= (1.9-0.16,1.9+0.16)
=(1.74, 2.06)
Last option — a decimal that terminates after three decimal places
Hope this helps good luck u can do thisss :)
Answer:
156.25
Step-by-step explanation:
Answer:
Jayden & brother went 12 or 13 times
Maria & sister went 12 or 13 times
