Set components equal:
![t = 8-s \\ 5-t = s-3 \\ 48 t^2 = s^2](https://tex.z-dn.net/?f=t%20%3D%208-s%20%5C%5C%20%205-t%20%3D%20s-3%20%5C%5C%20%2048%20t%5E2%20%3D%20s%5E2)
From this we find:
![t = 8-s \\ s = 4 \sqrt{3} t](https://tex.z-dn.net/?f=t%20%3D%208-s%20%5C%5C%20%20s%20%3D%20%204%20%5Csqrt%7B3%7D%20t)
Substitute and solve system:
![t = \frac{8}{1+4 \sqrt{3}} = 1.009 \\ \\ s = 8-t = 8 - 1.009 = 6.991](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B8%7D%7B1%2B4%20%5Csqrt%7B3%7D%7D%20%3D%201.009%20%20%5C%5C%20%5C%5C%20%20s%20%3D%208-t%20%3D%208%20-%201.009%20%3D%206.991)
The point where they intersect is:
The correct answer for the question that is being presented above is this one: "C.(162- 81pi/2) cm2." Figure WXYZ is equivalent to a rectangle with 2 quarter circles removed. The area of the shaded portion of the polygon or the rectangle is this: <span>C.(162- 81pi/2) cm2</span>
Answer:
(r-7) ÷ (6+?)
Step-by-step explanation:
I don't know what the last number is
A= 28.
The formula for the Pythagorean theorem is A^2 + B^2 = C^2
So plug in what you know. A^2 + 21^2 = 35^2 you get A^2+ 441 = 1225. You then take away 441 from 1225 and you get A^2 = 784. You have to find the square root of 784 which is 28. So side A is 28.