The area of a rhombus is 1/2 times the lengths of the diagonals
A = (1/2)(AC)(BD)
Since the diagonals bisect each other, and ed = 8, BD must be 16. Substituting in this for BD and the given area (168) we get the following:
168 = (1/2)(AC)16
168 = 8(AC)
21 = AC
Answer:
Step-by-step explanation:
(-1,5) (0,2)
y2= 2, y1 = 5, x2 = 0, x1 = -1
Slope m = [y2 - y1]/[x2 - x1]
m = {2 - 5}/{0+1}
m = -3/1
m = -3
And
y - y1 = m(x - x1)
y - 5 = -3(x + 1)
y - 5 = -3x - 3
y = -3x - 3 + 5
y = -3x + 2
Answer: floating variable.
Step-by-step explanation:
Answer:
15120
Step-by-step explanation:
Given:
The number of players at point guard = 10
The number of players at shooting guard = 12
The number of players at small forward = 7
The number of players at power forward = 2
The number of players at center = 9
Then, the number of different teams William could draft is given by:
10 x 12 x 7 x 2 x 9
William could draft 15120 different teams.
