A hexagon has 6 sides. The total angles have to equal 180. So it's 180/6 it equals 30.
Answer:
The solutions are x = -7 and x = -9
Step-by-step explanation:
All absolute values are non-negative numbers, so x + 8 will always be greater than 0. This means that |x + 8| = 1 can be represented as x + 8 = 1 AND x + 8 = -1.
x + 8 = 1 ⇒ x = -7
x + 8 = -1 ⇒ x = -9
So the solutions are x equals -7 or -9.
5 x 10,000 + 3 x 1,000 + 2 x 10 + 8 x 1 +
![6 \frac{1}{1000}](https://tex.z-dn.net/?f=6%20%5Cfrac%7B1%7D%7B1000%7D%20)
+ 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
you want to make the <span>
![6 \frac{1}{1000}](https://tex.z-dn.net/?f=6%20%5Cfrac%7B1%7D%7B1000%7D%20)
into a whole number:
</span><span>
![6 \frac{1}{1000}](https://tex.z-dn.net/?f=6%20%5Cfrac%7B1%7D%7B1000%7D%20)
= 6.001
</span>
new equation:
<span>5 x 10,000 + 3 x 1,000 + 2 x 10 + 8 x 1 + 6.001 + 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
</span>50,000 + <span>3 x 1,000 + 2 x 10 + 8 x 1 + 6.001 + 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
50,000 + 3,000 + </span><span>2 x 10 + 8 x 1 + 6.001 + 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
</span>50,000 + 3,000 + 20 + <span>8 x 1 + 6.001 + 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
</span>50,000 + 3,000 + 20 + 8 + <span>6.001 + 4 x
![\frac{1}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B1000%7D%20)
</span>50,000 + 3,000 + 20 + 8 + <span>6.001 + .004
</span>53,000 + 20 + 8 + 6.001 + .004
53,020 + 8 + 6.001 + .004
53,028 + 6.001 + .004
53,034 + .004
=53,034.005
The upper half of the ellipse has equation
![y=\dfrac ba\sqrt{a^2-x^2}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%20ba%5Csqrt%7Ba%5E2-x%5E2%7D)
with
, so that the volume of the solid (using the disk method) is
![\displaystyle\frac{\pi b}a\int_{-a}^a\left(\sqrt{a^2-x^2}\right)^2-0^2\,\mathrm dx=\frac{2\pi b}a\int_0^a(a^2-x^2)\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Cpi%20b%7Da%5Cint_%7B-a%7D%5Ea%5Cleft%28%5Csqrt%7Ba%5E2-x%5E2%7D%5Cright%29%5E2-0%5E2%5C%2C%5Cmathrm%20dx%3D%5Cfrac%7B2%5Cpi%20b%7Da%5Cint_0%5Ea%28a%5E2-x%5E2%29%5C%2C%5Cmathrm%20dx)
![\displaystyle=\frac{2\pi b}a\left(a^2x-\frac{x^3}3\right)\bigg|_0^a](https://tex.z-dn.net/?f=%5Cdisplaystyle%3D%5Cfrac%7B2%5Cpi%20b%7Da%5Cleft%28a%5E2x-%5Cfrac%7Bx%5E3%7D3%5Cright%29%5Cbigg%7C_0%5Ea)
![\displaystyle=\boxed{\frac{4\pi a^2b}3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%3D%5Cboxed%7B%5Cfrac%7B4%5Cpi%20a%5E2b%7D3%7D)
Answer:
in the first equation f(2)=6 is f=3
In second place the answer of that equation is f=1/3