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3 years ago

A can holds 3 tennis balls. A box holds 4 cans. A case holds 6 boxes. How many tennis balls are in 10 cases?

Mathematics

2 answers:

Korolek [52]3 years ago

5 0

Answer:

720 balls

Step-by-step explanation:

Can = 3 balls

Box = 4 cans = 4*3balls = 12 balls

Case = 6 boxes = 6* 12balls = 72 balls

10 cases = 10 *72balls = 720 balls

myrzilka [38]3 years ago

4 0

Answer: 720

Step-by-step explanation:

If there are 10 cases and 6 boxes in a case. Multiply 10 by 6 to get 60.

Then if there are 4 cans in a box. Multiply 4 by 60 to get 240.

Finally, if there are 3 tennis balls per can. Multiply 240 by 3 to get 720.

There are 720 Tennis Balls in 10 Cases.

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Use the given map to find the coordinates of a point that lies on the directed line segment from c to d and partitions the segme

Lelechka [254]

Given:

The line segment is passing through the points (-9,-3) and (8,5),

Divide the segment in the ratio of 1:4.

Use the formula,

$\begin{gathered} (\frac{mx_2+nx_1}{m+n},\frac{my_2-ny_1}{m+n}) \\ (x_1,y_1)=(-9,-3) \\ (x_2,y_2)=(8,5) \\ m\colon n=1\colon4 \end{gathered}$

It gives,

$\begin{gathered} (\frac{1(8)+4(-9)}{1+4},\frac{1(5)+4(-3)}{1+4}) \\ (-\frac{28}{5},-\frac{7}{5}) \end{gathered}$

Answer:

$(-\frac{28}{5},-\frac{7}{5})$

8 0

1 year ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

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BaLLatris [955]

Answer:

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omeli [17]

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Step-by-step explanation:

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