A certain disease has an incidence rate of 0.7%. If the false negative rate is 5% and the false positive rate is

If a boy has 4 pairs of shorts, 8 shirts, and 2 pairs of shoes, how many different outfits could he wear?

sveta [45]

Answer:

64

Step-by-step explanation:

I paired the first shirt with all of the pants and both shoes which was 8 outfits, but here are 8 other shirts which will also make 8 outfits.

4 0

3 years ago

Exactly 1 1/3 yard of ribbon is needed to make a bow. Which of the following lengths of ribbon could be used to make a bow with

svp [43]

Answer:

1 and 2/5 yards wastes only 1/15 a yard

Step-by-step explanation:

1 and 1/6 yards would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/10 yards would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)

1 and 2/5 yards

$1\frac{2}{5} -1\frac{1}{3} =\\\\1\frac{6}{15} -1\frac{5}{15} =\\\\\frac{1}{15}$

Wastes 1/15 a yard.

1 and 1/2 yards

$1\frac{1}{2} -1\frac{1}{3} =\\\\1\frac{3}{6} -1\frac{2}{6} =\\\\\frac{1}{6}$

It wastes 1/6 a yard.

2 yards

$2-1\frac{1}{3} =\frac{2}{3}$

It wastes 4/6 a yard.

4 0

3 years ago

Please make Y=x+12 and 4x+2y=27 into one equation.

tiny-mole [99]

So what you need to start with is taking the x from both sides as adding 12 to them. Then, you move the 27 over 4 decimals.

4 0

2 years ago

What is the solution of the system?

prisoha [69]

X=-4y+2
3(-4y+2)+2y=11
-12y+6+2y=11
-10y+6=11
-6=-6
-10y=5
y=-1/2

3x+2(-1/2)=11
3x-1=11
+1=+1
3x=12
x=4

Solution:(-1/2,4)

8 0

2 years ago

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago