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3 years ago

Help me PLEASEEEEEEEEEEEE :C

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

Answer: The answer is 525

gulaghasi [49]3 years ago

3 0

Answer:

A. 525 in squared

Step-by-step explanation:

Fundamentally, the area of a parellelogram such as this can be calculated the same way the area of a normal rectangle is calculated: Length x Width.

Thus,

(27 + 8) x 15 = Area

35 x 15 = Area

525 = Area

Don't forget your units! (Inches squared)

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The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

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$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
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\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
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\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
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\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
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\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
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$
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3 years ago

A? B? C? D? Number 10 on conexus <3 If correct I’ll give brainlest

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If a car goes 280 miles in 4 hrs how far could it go in 6 hrs and 30 mins

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