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NNADVOKAT [17]
3 years ago
9

The base of a triangle is 7 meters longer than the height of the triangle of the area of the triangle is 22 square meters what a

re the base and height of the triangle
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

given \\ heigh(h) = 7m \\ area \: of \: triangle \: (a) = 22m {}^{2}  \\ base(b) = x \\ a =  \frac{1}{2}  \times h \times b \\  \frac{a}{h}  =  \frac{1}{2}  \times b \\ b = 2( \frac{a}{h} ) \\ b = 2( \frac{22m {}^{2} }{7m} ) \\ b = 6.29m \\ base = 6.29m

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A b c or d? help me ​
kotegsom [21]

Answer:

B.) \frac{1}{2} +8

Step-by-step explanation:

\frac{1}{2}-(-8)

A negative and a negative equals a positive. Remove parentheses and simplify

\frac{1}{2}+8

Done.

7 0
2 years ago
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Convert 244 16 to decimal:
vlabodo [156]

Answer:

15.25 is your answer

Step-by-step explanation:

4 0
2 years ago
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PLZ HELP WITH THIS QUESTION!
Bad White [126]

Answer:

D

Step-by-step explanation:

Given the quadratic

d = - 16t² + 12t ← subtract d from both sides

- 16t² + 12t - d = 0 ← in standard form

with a = - 16, b = 12, c = - d

Use the quadratic formula to solve for t

t = ( - 12 ± \sqrt{12^2-(4(-16)(-d))}) / - 32

 = ( - 12 ± \sqrt{144-64d}) / - 32

 = ( - 12 ± \sqrt{16(9-4d)}) / - 32

 = ( - 12 ± 4\sqrt{9-4d}) / - 32

 = \frac{-12}{-32} ± \frac{4}{-32}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{1}{8}\sqrt{9-4d}

 = \frac{3}{8} ± \frac{\sqrt{9-4d} }{8} → D

8 0
3 years ago
MANY PTS AND BRAINLY FAST
Troyanec [42]

Answer:

Option C

Step-by-step explanation:

we have

-6x^{2} -6x+12=0

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-6x^{2} -6x=-12

step 2

Factor -6 leading coefficient'

-6(x^{2} +x)=-12

step 3

Complete the square

Remember to balance the equation by adding the same constants to each side

-6(x^{2} +x+0.25)=-12-1.5

-6(x^{2} +x+0.25)=-13.5

step 4

Rewrite as perfect squares

-6(x+0.5)^{2}=-13.5

simplify

(x+0.5)^{2}=2.25

5 0
3 years ago
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Find the center, vertices, and foci for the ellipse 25x^2+64y^2=1600
Ronch [10]

Answer:

Step-by-step explanation:

Answer:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                            25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                             x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                            

3.- Find a, b and c

   a² = 64             a = 8

   b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                  a² = b² + c²

-Solve for c

                  c² = a² - b²

-Substitution

                  c² = 8² - 5²

-Simplification

                 c² = 64 - 25

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-Result

                 c = √13

4.- Find the center

         C = (0, 0)

5.- Find the vertices

         V1 = (-8, 0)     V2 = (8, 0)

6.- Find the foci

         F1 = (-√13, 0)   F2 = (√13, 0)

4 0
3 years ago
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