Answer: b is right angel triangle 90 degrees
b - c is straight line that adds up to 180 degrees
9 is the height for sin, cos and sine
Step-by-step explanation:
<span>If triangle ABC is congruent to triangle XYZ
then
<A = <X
hope it helps</span>
Answer:
i just took the test the answer is A,B and C.
Step-by-step explanation:
i. Line BD = 6√2 cm
ii. Perimeter = 3 (π + 4) cm
iii. Area = 18 ( π - 2) cm
<h3>How to determine the parameters</h3>
Let the length of BD = x
Since B is the midpoint of the arc AC, then ∠BOC = 15°
In ΔBDB
Let's use the trigonometric ration, tan
![Tan 45 = \frac{BD}{CD}](https://tex.z-dn.net/?f=Tan%2045%20%3D%20%5Cfrac%7BBD%7D%7BCD%7D)
CD = x
Then, using the Pythagorean theorem
![x^2 + x^2 = 12^2](https://tex.z-dn.net/?f=x%5E2%20%2B%20x%5E2%20%3D%2012%5E2)
![2x^2 = 144](https://tex.z-dn.net/?f=2x%5E2%20%3D%20144)
![x^2 = \frac{144}{2}](https://tex.z-dn.net/?f=x%5E2%20%3D%20%5Cfrac%7B144%7D%7B2%7D)
![x = \sqrt{72}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B72%7D)
![x = \sqrt{36 *2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B36%20%2A2%7D)
![x = 6\sqrt{2}](https://tex.z-dn.net/?f=x%20%3D%206%5Csqrt%7B2%7D)
Thus, line BD is
cm
ii. Perimeter = BC + BD + CD
= 2πr/8 + x + r - x
= π(12)/4 + r
= 3π + 12
= 3 ( π + 4) cm
iii. Area of shaded area = Area of BOC + Area of BOD
⇒ πr^2/8 × 1/2x^2
= π144/8 × 1/2(72)
= 18π - 36
= 18 ( π - 2) cm²
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