A has the value of 51. 10/10= 1+50=51
9514 1404 393
Answer:
24
Step-by-step explanation:
The product of lengths from the point where the secants meet to the near and far circle intersection points is the same for both secants.
RQ·RC = RS·RT
8(27) = (3x)(8x)
9 = x^2 . . . . . . . . . divide by 24
3 = x
Then the length of interest is ...
TR = 8x = 8·3
TR = 24
firstly, I'd like to point out the graph is misleading, if AC is 10 it should be the shorter sides, but it shows as the longer side there.
let's bear in mind that in a rhombus, all sides are equal, even though they may be slanted, the diagonals meet at right-angles always, so the center is simply four 90° angles, and the diagonals bisect each other, namely they cut each other in equal halves.
check the picture below.
The point-slope form:

We have

Therefore
<h3>slope = -3 and the point (-2, 6)</h3>
------------
<h3>y + 2 = 2(x - 1)</h3>
2x - y = 4 <em>it's standard form Ax + By = C</em>
y = 2x - 4 <em>it's slope-intercept form y = mx + b</em>
y - x = 4 →<em> </em>x - y = -4 <em>t's standard form Ax + By = C</em>