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juin [17]
3 years ago
7

mariah has been hired as a receptionist.She is paid a flat rate of $225 each week and ears an additional $11.25 for every hour t

hat she works. If her goal is to make 675 in one week which equation will help Mariah determine the number of hours she must work?
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0
675 = 225 + 11.25h <== ur equation
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Multiply. (−17)⋅(−6) −102 −23 23 102
KATRIN_1 [288]

To multiply: (-17)\times(-6)

The multiplication of 17\times6 is attached into the figure.

Now, since, 17 \times 6 = 102

Then, (-17) \times (-6) = 102


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Insert parentheses to make each statement true. 6+7•4-2=26
blagie [28]
Around the 4-2. 7+6=13•2=26 ;)
4 0
2 years ago
Read 2 more answers
Is -2 a solution of the inequality -2x + 5 &gt; 9?<br> A. yes<br> | B. no
kramer

Answer:B

Step-by-step explanation:

-2x+5>9

-2x>4

-x>2

x<-2

3 0
3 years ago
I don’t understand how to do this at all.
avanturin [10]

Answer:

2m

Step-by-step explanation:

(m+3) (m-1)

We need to FOIL

first m*m = m^2

outer -1*m  = -m

inner = 3m

last 3*-1 = -3

Add these together

m^2 -m +3m -3

m^2 +2m -3

3 0
3 years ago
Use the Chain Rule (Calculus 2)
atroni [7]

1. By the chain rule,

\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}

I'm going to switch up the notation to save space, so for example, z_x is shorthand for \frac{\partial z}{\partial x}.

z_t=z_xx_t+z_yy_t

We have

x=e^{-t}\implies x_t=-e^{-t}

y=e^t\implies y_t=e^t

z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}

\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0

Similarly,

w_t=w_xx_t+w_yy_t+w_zz_t

where

x=\cosh^2t\implies x_t=2\cosh t\sinh t

y=\sinh^2t\implies y_t=2\cosh t\sinh t

z=t\implies z_t=1

To capture all the partial derivatives of w, compute its gradient:

\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}

\implies w_t=\dfrac1{\sqrt{-2t-t^2}}

2. The problem is asking for \frac{\partial z}{\partial x} and \frac{\partial z}{\partial y}. But z is already a function of x,y, so the chain rule isn't needed here. I suspect it's supposed to say "find \frac{\partial z}{\partial s} and \frac{\partial z}{\partial t}" instead.

If that's the case, then

z_s=z_xx_s+z_yy_s

z_t=z_xx_t+z_yy_t

as the hint suggests. We have

z=\sin x\cos y\implies\begin{cases}z_x=\cos x\cos y=\cos(s+t)\cos(s^2t)\\z_y=-\sin x\sin y=-\sin(s+t)\sin(s^2t)\end{cases}

x=s+t\implies x_s=x_t=1

y=s^2t\implies\begin{cases}y_s=2st\\y_t=s^2\end{cases}

Putting everything together, we get

z_s=\cos(s+t)\cos(s^2t)-2st\sin(s+t)\sin(s^2t)

z_t=\cos(s+t)\cos(s^2t)-s^2\sin(s+t)\sin(s^2t)

8 0
3 years ago
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