PLEASE PLEASE HELP ME! (brainliest) (functions)
2 answers:
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<span><u><em>Answer:</em></u>
It represent the tens of the number, therefore, it's unit value is 30
<u><em>Explanation:</em></u>
The place value chart is added in the attached image.
<u>Checking this chart, we would find that:</u>
first digit from the right is the units of the number
second digit from the right is the tens of the number
third digit from the right is the hundreds of the number
Comparing this with the nuber given, we would find that the 3 is in the tens position. Therefore, it unit value is 30.
<u>Another way to answer this is by breaking the number given as follows:</u>
432 = 400 + 30 + 2
We can note that the unit value of the 3 is 30
Hope this helps :)</span>
It represent the tens of the number, therefore, it's unit value is 30
<u><em>Explanation:</em></u>
The place value chart is added in the attached image.
<u>Checking this chart, we would find that:</u>
first digit from the right is the units of the number
second digit from the right is the tens of the number
third digit from the right is the hundreds of the number
Comparing this with the nuber given, we would find that the 3 is in the tens position. Therefore, it unit value is 30.
<u>Another way to answer this is by breaking the number given as follows:</u>
432 = 400 + 30 + 2
We can note that the unit value of the 3 is 30
Hope this helps :)</span>
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.
1. Draw the angle bisector of angle JKL. The straight line in the green one.
2. Draw the angle bisector of angle KLJ. The straight line in the blue one.
3. Draw point D at these two lines.
4. Draw a line through point D perpendicular to side JK. The straight line in the red one.
5. Mark point G at the red line and side JK.
6. Draw a circle with center at D (point of concurrency) and a radius of DG.
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To circumscribe a circle in the attached triangle, we must follow the following steps:
1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.
2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.
3. The center of the circle is the intersection of these two lines
4. Draw a circle with center at D (point of concurrency).
<h3>3. Construct the two lines tangents to circle</h3>A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.