Where must the fulcrum be located if a 300-pound weight and a 450-pound
1 answer:
Answer:
9 foot.
Step-by-step explanation:
From the question given, we were told that a 300-pound weight and a 450-pound weight are placed on each end of a 15-foot bar.
The diagram illustrating the question can be seen on the attached photo.
Weight 1 (W1) = 300 pound
Weight 2 (W2) = 450 pound.
Distance to which the fulcrum must be placed in order to balance (d1) = x
Distance from the other side of the bar (d2) = 15 – x
W1d1 = W2d2
300 × x = 450 (15 – x)
Clear bracket
300x = 6750 – 450x
Collect like terms
300x + 450x = 6750
750x = 6750
Divide both side by the coefficient of x i.e 750
x = 6750/750
x = 9 foot.
Therefore, the fulcrum must be placed at 9 foot in order to balance the bar.
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Answer:
0.034921 miles or 1843774 feet tall
Step-by-step explanation:
Using trigonometric functions we know that and
where
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First we will calculate the hypotenuse using the x equation, since we know x = 1 mile (distance from the building on the ground) we have:
Now we will calculate the height of the building using the y equation and so:
The building is 0.034921 miles or approximately 184.3774 feet tall.
C is the correct answer
we should find the area of the square and then divide it by 24.
(360/15=24)
good luck
we should find the area of the square and then divide it by 24.
(360/15=24)
good luck