Where must the fulcrum be located if a 300-pound weight and a 450-pound
1 answer:
Answer:
9 foot.
Step-by-step explanation:
From the question given, we were told that a 300-pound weight and a 450-pound weight are placed on each end of a 15-foot bar.
The diagram illustrating the question can be seen on the attached photo.
Weight 1 (W1) = 300 pound
Weight 2 (W2) = 450 pound.
Distance to which the fulcrum must be placed in order to balance (d1) = x
Distance from the other side of the bar (d2) = 15 – x
W1d1 = W2d2
300 × x = 450 (15 – x)
Clear bracket
300x = 6750 – 450x
Collect like terms
300x + 450x = 6750
750x = 6750
Divide both side by the coefficient of x i.e 750
x = 6750/750
x = 9 foot.
Therefore, the fulcrum must be placed at 9 foot in order to balance the bar.
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Answer:
- As the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship.
- As the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship.
Step-by-step explanation:
<u><em>Solving equation A: y = x </em></u>
Let us consider the given equation A:
y = x
- Putting x = 1 in y = x
y = x
y = 1 ∵ x = 1
Hence, (1, 1) is the ordered pair of y = x
- Putting x = 2 in y = x
y = x
y = 2 ∵ x = 2
Hence, (2, 2) is the ordered pair of y = x
- Putting x = 3 in y = x
y = x
y = 3 ∵ x = 3
Hence, (3, 3) is the ordered pair of y = x
- Putting x = 4 in y = x
y = x
y = 4 ∵ x = 4
Hence, (4, 4) is the ordered pair of y = x
- Putting x = 5 in y = x
y = x
y = 5 ∵ x = 5
Hence, (5, 5) is the ordered pair of y = x
Lets us consider all the ordered pairs i.e. (1, 1), (2, 2), (3, 3), (4, 4) and (5, 5) to make a table for y = x.
<em>y x</em>
1 1
2 2
3 3
4 4
5 5
As from the table, lets take the ratio of every point i.e. y/x
- For (1, 1), the ratio will be y/x ⇒ 1/1 = 1
- For (2, 2), the ratio will be y/x ⇒ 2/2 = 1
- For (3, 3), the ratio will be y/x ⇒ 3/3 = 1
- For (4, 4), the ratio will be y/x ⇒ 4/4 = 1
- For (5, 5), the ratio will be y/x ⇒ 5/5 = 1
Hence, the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship. Please also check the graph in attached<em> figure a.</em>
<u><em>Solving equation A: y = x +2</em></u>
Let us consider the given equation A:
y = x + 2
- Putting x = 1 in y = x + 2
y = x + 2
y = 1 + 2 ⇒ 3 ∵ x = 1
Hence, (1, 3) is the ordered pair of y = x + 2
- Putting x = 2 in y = x + 2
y = x + 2
y = 2 +2 ⇒ 4 ∵ x = 2
Hence, (2, 4) is the ordered pair of y = x + 2
- Putting x = 3 in y = x + 2
y = x + 2
y = 3 + 2 ⇒ 5 ∵ x = 3
Hence, (3, 5) is the ordered pair of y = x + 2
- Putting x = 4 in y = x + 2
y = x + 2
y = 4 + 2 ⇒ 6 ∵ x = 4
Hence, (4, 6) is the ordered pair of y = x + 2
- Putting x = 5 in y = x + 2
y = x + 2
y = 5 +2 ⇒ 7 ∵ x = 5
Hence, (5, 7) is the ordered pair of y = x + 2
Lets us consider all the ordered pairs i.e. (1, 3), (2, 4), (3, 5), (4, 6) and (5, 7) to make a table for y = x + 2.
<em>y x + 2</em>
1 3
2 4
3 5
4 6
5 7
As from the table, lets take the ratio of every point i.e. y/x
- For (1, 3), the ratio will be y/x ⇒ 3/1 = 3
- For (2, 4), the ratio will be y/x ⇒ 4/2 = 2
- For (3, 5), the ratio will be y/x ⇒ 5/3 = 5/3
- For (4, 6), the ratio will be y/x ⇒ 6/4 = 3/2
- For (5, 7), the ratio will be y/x ⇒ 7/5 = 7/5
Hence, the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship. Please also check the graph in attached<em> figure a.</em>
<em>Keywords: equation, graph</em>
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