First you have to subtract 1350-1000 to get 350. Then you have to make 350/1000 into a percent. First you have to turn it into a decimal. In the fraction 350/1000 can be reduced to 35/100. In decimal form it would be 0.35. In pecentage form it would be 35%. The percentage difference of the student population would be 35%.
Parallel lines have the same slope, so the slope of the other line is also 1/6
Answer:
The answer to your question is: 3.7 hours
Step-by-step explanation:
Kam can make 72 cookies/ 3 hours
Madison can make 120 cookies/4 hours
Time to make 200 cookies together = ?
First, calculate the number of cookies make per hour
Kam 72 ---------------- 3
x ---------------- 1 hour
x = 72/3 = 24 cookies/h
Madison
120 ------------- 4 hours
x --------------- 1 hour
x = 120 / 4 = 30 cookies
Now we write and equation where "t" will be time
24t + 30t = 200 and solve it
54t = 200
t = 200/54
t = 3.7 hours
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
