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belka [17]
3 years ago
5

Two pieces of equipment were purchased for a total of $4000. If one piece cost $850 more than

Mathematics
1 answer:
ruslelena [56]3 years ago
3 0

The price of less expensive equipment is $1575.

Step-by-step explanation:

Let,

Price of one equipment = x

Price of other equipment = y

According to given statement;

x+y=4000   Eqn 1

x = y+850    Eqn 2

Putting Eqn 2 in Eqn 1

(y+850)+y=4000\\y+850+y=4000\\2y=4000-850\\2y=3150

Dividing both sides by 2;

\frac{2y}{2}=\frac{3150}{2}\\y=1575

Putting y=1575 in Eqn 2;

x=1575+850\\x=2425

The price of less expensive equipment is $1575.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/11343416
  • brainly.com/question/11416224

#LearnwithBrainly

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The length of a rectangle is 2 inches more than 4 times the width. The perimeter is 64 inches. Find the length and the width.
pashok25 [27]
<span>The width is 6 inches and the length is 26 inches.

Explanation:
L=4w+2, since the length is 2 more than 4 times the width.

The perimeter is given by P=2L+2w; using our equation for L, we have
P=2(4w+2)+2w.

Using the distributive property, we have
P=2*4w+2*2+2w
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Combining like terms, we have P=10w+4.

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Subtract 4 from both sides:
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Substitute this into the equation for length: L=4*6+2=24+2=26</span>
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3 years ago
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A rectangle has length (x + 5)cm and width (x –2)cm. Its area is 60 cm 2
Ksivusya [100]

Area = length x width

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Subtract 60 from both sides:

x^2 +3x -70 = 0

Solve for x by finding 2 numbers when added together = 3 and when multiplied by each other = -70

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3 years ago
If the length of a rectangle is 3 feet less then twice its width and the area is 54square feet what are its dimensions
erma4kov [3.2K]
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Now solve for W by factoring (or by applying the quadratic formula):
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Factor out a common 2W from the first two terms and a 9 from the last two terms:
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Regroup the terms to get our fully factored equation:
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This gives us the roots W = 6 and W = -9/2, but width can't be negative so we have width = 6 ft. Then remember that the length L = 2W - 3, so our length is:
L = 2W - 3 = 2(6) - 3 = 12 - 3 = 9
So now we know that our rectangle is 9 feet long and 6 feet wide.
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