2 years ago

An inverse variation includes the points (15,1) and (n,5). Find n

1 answer:

7 0

Inverse variation: y=k/x

1. plug in the values: (15,1)
1=k/15

2. solve for k

3. Now, plug in what you can for the second point: (n,5)
5=k/n (if you do the step above, you will know “k”.

4. Solve for “n”

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20

Alenkinab [10]

Answer:

${ x^2+3x-4}$

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

$\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }$

= $\frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}$

= $\frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}$

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= ${ (x-1)(x+4)}$

= ${ x^2+3x-4}$

3 0

3 years ago

Read 2 more answers

Suppose that a student has $150 in a band savings account at the start of the school year. Calculate the change in that savings

Iteru [2.4K]

Total after interest would be $157.5

8 0

3 years ago

4x-8 = 12 4x - 8 + 8 = 12 + 8 4x= 20 4/4x=20/4 x=

TEA [102]

Answer:

x=5

i just got it right on my quiz

5 0

3 years ago

A wheel of diameter 50.0 cm starts from rest and rotates with a constant angular acceleration of 2.00 rad/s^2. At the instant th

Kruka [31]

R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²

8 0

3 years ago

5. Factor x²-x-72 (x-8)(x+9) (x-6)(x+12) (x+6)(x-12) (x+8)(x-9)

Artyom0805 [142]

Answer:

(x + 8)(x - 9)

Step-by-step explanation:

(x+8)(x-9)

= x² - 9x + 8x - 72

= x² - x - 72

Then

The factorization of x² - x - 72 is (x+8)(x-9)

5 0

2 years ago