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velikii [3]
3 years ago
13

RATIOS MY WORST ENEMY HELP!!! IM SO LOST

Mathematics
1 answer:
Pavel [41]3 years ago
4 0
(4,6) (6,9) (8,12)
Now for rick it is (6,8) (9,12) (12,16)
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Divide 2/8 by 9/18 . Input your answer as a reduced fraction.\
Katen [24]

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{2}{8}\div\frac{9}{18}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Simplify \ \frac{2}{8} \ to \ \frac{1}{4}. \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\div\frac{18}{9}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: a\div \frac{b}{c}=a\times \frac{c}{b}a \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{4}\times\frac{18}{9}   }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Use \ this \ rule: \frac{a}{b} \times \frac{c}d{}=\frac{ac}{bd}. \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1\times18}{4\times9} \ \to \ \ Multiply  }} \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{ \frac{18}{36}= }}\boxed{\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{\frac{1}{2}  }} \end{gathered}$}} \end{gathered}$}

8 0
2 years ago
Read 2 more answers
The decimal equivalent 3/5 is a repeating decimal true or false?
Svetlanka [38]

Answer: false

Step-by-step explanation:

3/5 in a decimal is 0.6. overall 0.6 is not an repeating decimal.

4 0
3 years ago
Mathematical induction, prove the following two statements are true
adelina 88 [10]
Prove:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}
____________________________________________

Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}

Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}
3 0
3 years ago
Need help ASAP!!!!!!!
marin [14]

Answer:

1. 3   2. 16

Step-by-step explanation:

3x+2/y, x = 3 and y = 6

3(3)/6

Factor the number

3*3*2/3*2

Cancel the common factor (3)

3*2/2

Cancel the common factor (2)

3/1

Simplify

=3

(4a)^3/(b-2), a = 2, b = 4

(4(2)^3/(4-2)

Subtract the numbers:

2^3 * 4/2

Apply exponent rule (a^b*a^c=a^b+c)

= 2^3+1

Add the numbers:

2^4

Simplify:

=16

8 0
3 years ago
Your quiz grades are a 63% and an 87% what's ur grade average
Fantom [35]

Answer:

75 is your grade average.

Step-by-step explanation:

To find the average you add up all the numbers you have and then divide the sum of those numbers by the number of all the numbers you have. (I hope that made sense).

63

+ 87

_____

150

150/2 = 75%

6 0
3 years ago
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